# arrow_back Solve for $x$ in the quadratic equation $x^{2}+10 x+8=0$

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Solve for $x$ in the quadratic equation $x^{2}+10 x+8=0$

## 1 Answer

Best answer

Best answer

Answer:

$x=-0,88$ or $x=-9,12$

Explanation:

\begin{aligned} x^{2} &+10 x+8=0 \\ x &=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a} \\ &=\frac{-10 \pm \sqrt{10^{2}-4(1)(8)}}{2(1)} \\ &=\frac{-10 \pm \sqrt{68}}{2} \\ x &=-0,88 \text { or } x=-9,12 \end{aligned}

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